How do you calculate 15,6,9,3 as 24 points?

Mondo Social Updated on 2024-01-31

Search Topic Full Time Challenge December

The four numbers given in this question are 15, 6, 9, 3, how to get 24 points through various operations?Usually we count 24 points to give the number is no more than 13, because this game was originally a random draw of four cards from the playing cards, there is a 15 in this problem, it may also be an extended 24 point play, how to calculate?The following algorithm comes to mind:

The first algorithm:

Using only addition and division, the addition of 15 and 6 is 21, the division of 9 and 3 is 3, and the addition of 21 and 3 gives 24, the specific equation is as follows:

First, 15 + 6 = 21

Second, 9 3 = 3

Then, 21+3=24

The sum is: 15 + 6 + 9 3 = 24

It can also be shifted: 15 + 9 3 + 6 = 24

The second algorithm:

Using addition, subtraction and multiplication, the multiplication of 3 and 6 is 18, the subtraction of 18 and 9 is 9, and the addition of 15 and 9 gives 24, the specific equation is as follows:

First, 3*6=18

Second, 18-9=9

Then, 15 + 9 = 24

The sum is: 15 + 3 * 6-9 = 24

It can also be shifted: 15 + 9 3 + 6 = 24

The third algorithm:

Using addition and factorial operations, the addition of 9 and 6 in the problem is 15, the division of 15 and 15 is 1, 1 and 3, and the addition of 4 and 4 is 24, the specific equation is as follows:

First, 9+6=15

Secondly, 15 15 = 1

Then, (3+1)!=24

It all adds up: (15 (9+6)+3)!=24

It is also possible to shift: ((15-9) 6+3)!=24

Or: ((15-6) 9+3)!=24

Fourth algorithm:

Using addition and subtraction, open squared and factorial operations, the subtraction of 9 and 6 is 3, the division of 3 and 3 is 1, the addition of 1 and 15 is 16, and the square root of 16 is 4, and the factorial of 4 is 24, the specific equation is as follows:

First, 9-6 = 3

Secondly, 3 3 = 1

Then, (15+1))!=24

It all adds up to: ( 9-6) 3+15))!=24

It can also be shifted: ( 9-3) 6+15)))!=24

Or: ( 6+3) 9+15))!=24

There may be a lot of solutions, and at the moment I have thought of these four different algorithms, I hope to inspire you, what other different methods do you have?Welcome to leave a message in the comment area.

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