We can all get hooked on math.
This is a geometry problem for finding the shadow area in elementary school.
As shown in the figure, the right-angled triangle ABC moves to the lower left to obtain the triangle def, known: BC=16cm, if GC=6cm, GF=3cm, find the area of the shaded part.
Do you have any good solutions to the problem, share it!
Solution: shaded area = area of trapezoidal BEFG, BG=bc-gc=16-6=10, then S shadow=1 2 3 (10+16)=39.
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