During this time, some parents and friends of primary school students asked if they wanted to teach their children some mathematics to expand their knowledge, not limited to what they learned in class. Is there any activity or competition that can be recommended. My personal suggestion is to learn about the AMC8 American Mathematics Competition. There are several main reasons:
One is that this competition is organized by the American Mathematical Association (MAA) and has global influence.
The second is that the difficulty of this competition is medium, which is much simpler than the domestic Olympiad, and it is easy for children to get high scores with a little preparation.
The third is that it is easy to participate in this competition, ** registration, participation at home, and the cost is only 120 yuan.
Fourth, the content of the competition covers a wide range of topics, and the topics are both flexible and interesting, which is easy to stimulate children's interest in learning. Corresponding to the 8th grade mathematics knowledge system in the United States, the child's initial learning will also greatly promote the in-class learning in the primary and junior high school stages.
Fifth, self-study, parents can teach their children to get started, do not have to spend thousands of tickets to participate in the training class, it can be regarded as a parent-child activity, ha (the child said: you don't come over).
Combined with years of training and tutoring experience, I have compiled more than 20 years of AMC8 past papers and analyses into multiple versions, which is convenient for children to practice repeatedly, cultivate interest and master knowledge. I will continue to share relevant knowledge and content. I hope it can help everyone. For children who want to understand or participate in the AMC8 American Mathematics Competition, it is one of the most scientific and effective ways to prepare for the AMC8 past papers. With fragmented time, one year is enough to do well in the 2025 AMC8 competition through self-study. See the end of this article for details.
Today, let's continue to randomly look at the five AMC8 real questions and analysis.
This question is about arithmetic. Choose C. A little observation, you will find that the middle and upper terms can be eliminated:
So the final result = 2006 2 = 1003.
The test point for this question is plane geometry. I choose e.
Write out the axes of symmetry for each option graph in turn: an equilateral triangle has 3 axes of symmetry. A non-square rhombus has 2 axes of symmetry. A non-square rectangle has 2 axes of symmetry. An isosceles trapezoidal has 1 axis of symmetry. A square has 4 axes of symmetry. Therefore, the answer is E.
The test point for this question is number theory (prime numbers). Choose A.
If these 2 prime numbers do not contain 2, they are 2 odd prime numbers, then their sum should be even, and 10001 is an odd number. If one of the prime numbers is 2, then the other prime number is 10001-2=9999, but it is not an odd number, resulting in a contradiction.
To sum up, it is impossible to write 10001 as the sum of 2 prime numbers, choose a.
This question is about probability. Pick B.
According to the meaning of the title, the last draw must be red. Depending on how many times the last red is drawn, we categorize and discuss as follows:
The last 1 red is drawn for the third time, which means that the first 3 times are all red, so the probability is: p1 = 3 5 * 2 4 * 1 3 = 1 10
The last 1 red is drawn for the 4th time, which means that 2 of the first 3 times are red, so the probability is: p2=c(3,2) c(5,2)=3 10
The last 1 red is drawn for the 5th time, which means that all the green has been drawn in the previous 4 times, which is not in accordance with the rules, because it stops after drawing 2 greens, so this will not happen.
To sum up, the total probability p=p1+p2=1 10+3 10=2 5, choose b.
Warm reminder: This kind of classification discussion of probability problems often appears, and reading the problem is the most important part of solving the problem, and it should be experienced repeatedly.
This question is about probability, choose D.
If the product is 0, the selected number must have 0, and once 0 is selected, then there are only 5 options for the second number. The total method of selecting 2 numbers from 6 numbers is c(6,2)=15 methods, so the probability of the problem is 5 15 = 1 3. Pick D.
The above-mentioned six-point growth exclusive production of ** practice questions, in line with learning and cognitive psychology, ** in the complete calendar year AMC8 and AMC10 past questions, and will continue to update. AMC8 exam preparation is available, and repeated practice is also conducive to the improvement of mathematics ability in primary and junior high schools.