1) The reagent that can be added instead of H2O2 in the oxidation process is a strong oxidant;
2) According to the data in the table, Fe3+ and Al3+ are completely precipitated when pH=8The principle of Na ion exchange resin is Mn++NNANR MR+NNA, according to which the impurity ions are removed by exchange
3) In the reduction process, the valency of CR element changes from +6 to +3, then every 1728 g Cr2O7 2-metastasis48mol electrons, combined with the law of conservation of mass to write the reaction equation;
4) The electron-losing oxidation reaction occurs at the anode of the electrolytic cell: 2e = 2oh, and the electrode reaction formula on the cathode is: cr o +14h + 6e = 2cr +7h o.
Solution: (1) A sodium peroxide reacts with water to form sodium hydroxide and oxygen, which can play an oxidizing role, so a is correct;
b nitric acid has strong oxidation, and will oxidize ferrous ions into ferric ions in solution, which cannot achieve the purpose of the experiment, so b is wrong;
c ferric chloride does not decompose in water to produce oxygen, and the purpose of oxidation cannot be achieved, so c is wrong;
d potassium permanganate will undergo its own redox reaction after being dissolved in water, and will not produce oxygen, so d is wrong, and the answer is a;
2) According to the data in the table, Fe3+ and Al3+ are completely precipitated when pH=8It is known that the principle of sodium ion exchange resin is explained as m + nnanr mr + nna, then the impurity ions that are exchanged in this step are fe and al, and the answer is ab;
3) In the reduction process, the valency of CR element changes from +6 to +3, then every 1728g is 1728 294=(n 50) 2 gets 48mol electrons, so the amount of chromium ion species obtained is 50=048mol, according to the conservation and trimming of the number of atoms, the ionic equation of the reaction is: cr o +6cl +14h =2cr +3cl +7h o;
4) If the solution contains 01 mol cr o, then all the cations generated are converted into precipitate mass
0.1 mol×2×（60 g/mol-52 g/mol）]÷6-3）×3=0.8 g, so the answer is: (1) a;
2）ab；3）cr_o_^+6cl^+14h^=2cr^+3cl_↑+7h_o；