Take the xx brand RCU120SY2 as an example:Condensation: 37 Evaporation: 7 Evaporator: q = 316000 kcal h, q = 632m3 h condenser: q = 393000 kcal h, q = 786m3 h, these can be found in the manual of the xx brand; If the xx brand cooling tower is selected: 786×1.2 = 94.32 m3 h (water flow per hour) Marley SR-100 can meet (or other series of towers of the same specification, such as SC-100L) when selecting water pumps to leave 10% of the margin in the 100 tons of water of SR-100, in the relatively low head can choose the pipeline pump, in the high head should choose the IS pump. 100×1.1=110 tons of water per hour, the pipeline pump GD125-20 can be satisfied;
And when you only know the evaporator Q=316000kcal h, you can calculate how big the cooling tower needs by the following formula: 316000 125 (constant value) = 395000 kcal h, 125 - condenser load factor 395000 5 = 79000 kg h = 79 m3 h79 12 (margin) = 948m3 h (cooling tower water flow) electric refrigeration host - through-type: horsepower 2700 12×1.25 5000 or 3024 12×1.25 5000= cooling tower water flow m3 h).
The cooling tower is known to determine the cooling tower based on its conditionsCirculating waterThe usual formula for the amount:a.Cooling water = main engine cooling capacity (kw) 12×1.25×861/5000（m3/h）b.Cooling water volume = main condenser heat load (kcal h) 12/5000（m3/h）c.Cooling water volume = heat load of main engine condenser (m3 h) 12（m3/h）d.Cooling water = host refrigeration capacity (refrigeration tons) 08（m3/h）e.Cooling water volume = host evaporator heat load (kcal h) 15×1.25/5000（m3/h）f.Cooling water volume = heat load of the main evaporator (m3 h) 12×1.25（m3/h）g.Cooling water volume = host evaporator heat load (cooling tons) 12×1.25×3024/5000（m3/h）Note: Above: 12 is the selection margin 125 is the condenser load factor.
q=cm(t2-t1)t is the time, that is, how much time is needed to cool down; The calculated cooling capacity is measured in kcal h, which is then divided by 086 is the cooling capacity (W); If it's air-cooled, divide it by 2500, and it's the number of horses; If it is water-cooled, divide it by 3000, which is the number of horses; Q unit j; The cooling tower c is hot, if it is water, it is 42kj/k*kg ；t2-t1 is the cooling difference. Cooling capacity = q 42/t。